X^2+5x+4.5=0

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Solution for X^2+5x+4.5=0 equation: 



X^2+5X+4.5=0

a = 1; b = 5; c = +4.5;
Δ = b2-4ac
Δ = 52-4·1·4.5
Δ = 7
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{7}}{2*1}=\frac{-5-\sqrt{7}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{7}}{2*1}=\frac{-5+\sqrt{7}}{2}
$

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